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64m^2-1/16=0
We multiply all the terms by the denominator
64m^2*16-1=0
Wy multiply elements
1024m^2-1=0
a = 1024; b = 0; c = -1;
Δ = b2-4ac
Δ = 02-4·1024·(-1)
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4096}=64$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-64}{2*1024}=\frac{-64}{2048} =-1/32 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+64}{2*1024}=\frac{64}{2048} =1/32 $
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